Reactions of Ethers-Ether Cleavage

Ethers can be converted to alkyl halides when treated with HBr and HI in a sequence of two substitution reactions:

 

 

This transformation represents two substitution reactions. First, the ether is converted into an alkyl halide and an alcohol, which further reacts with the excess HX acid to form another equivalent of an alkyl halide:

 

 

When the reaction with HI is carried out at lower temperatures, the initial alcohol may be isolated as it does not further react with the acid.

 

 

What is the Mechanism of Ether Cleavage?

Ethers, just like the alcohols, are not suitable for direct nucleophilic substitution since the alkoxy groups are strong bases and therefore, poor leaving groups. For example, if we treat an ether with a good nucleophile, no reaction will occur since the cyanide cannot kick out the RO-alkoxide ion:

 

 

The analogy with alcohols is the poor leaving group ability of the OH group. However, again, like the alcohols, we can convert alkoxides into good leaving groups. And, while there are different ways of converting the OH into a good leaving group, such as the mesylation/tosylation, reaction with PBr3 and SOCl2, ethers are less reactive and it is only done by reacting them with strong acids HBr and HI.

 

 

The ether cleavage is a substitution reaction where the OR group is replaced with a halogen by converting it into a good leaving group first. This leaving group is an alcohol (initially formed as an oxonium ion in the ether), which is then replaced by the halide ion. It can occur by both SN2 and SN1 mechanisms depending on the identity of the R group.

If the R groups are methyl or primary alkyl groups, the reaction goes by the SN2 mechanism:

 

 

Tertiary ethers react by an SN1 mechanism and under milder conditions (lower temperatures, more dilute acid). This is explained by the higher stability of tertiary carbocations, which we have seen in the reaction of tertiary alcohols with HX acids and in the SN1 mechanism in general

For example, when tert-butyl methyl ether is reacted with HI, a tertiary alkyl halide is formed with methanol because the SN1 reaction occurs faster than competing SN2 substitution.

 

 

The methyl (or primary alcohol) is converted into an alkyl halide by an SN2 mechanism:

 

 

These patterns show how the reaction of ethers and alcohols with HX acids is nearly identical. You can check them in the following post for more comparison details:

Reactions of Alcohols with HCl, HB,r, and HI Acids

 

Check Also

 

Reactions of Alcohols

Ethers and Epoxides

 

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